3y+2(2y-5)+1=40

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Solution for 3y+2(2y-5)+1=40 equation: 



3y+2(2y-5)+1=40

We move all terms to the left:

3y+2(2y-5)+1-(40)=0

We add all the numbers together, and all the variables

3y+2(2y-5)-39=0

We multiply parentheses

3y+4y-10-39=0

We add all the numbers together, and all the variables

7y-49=0

We move all terms containing y to the left, all other terms to the right

7y=49

y=49/7

y=7

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