2(4d-1)/3=9(d+1)/4

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Solution for 2(4d-1)/3=9(d+1)/4 equation: 



2(4d-1)/3=9(d+1)/4

We move all terms to the left:

2(4d-1)/3-(9(d+1)/4)=0

We calculate fractions


8d/()+(-(9(d+1)*3)/()=0



We calculate terms in parentheses: +(-(9(d+1)*3)/(), so:

-(9(d+1)*3)/(

We multiply all the terms by the denominator


-(9(d+1)*3)



We calculate terms in parentheses: -(9(d+1)*3), so:

9(d+1)*3

We multiply parentheses

27d+27

Back to the equation:

-(27d+27)



We get rid of parentheses

-27d-27

Back to the equation:

+(-27d-27)



We get rid of parentheses

8d/()-27d-27=0

We multiply all the terms by the denominator


8d-27d*()-27*()=0

We add all the numbers together, and all the variables

8d-27d*()=0

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