7(y+2)=2(8y-8)+7y

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Solution for 7(y+2)=2(8y-8)+7y equation: 



7(y+2)=2(8y-8)+7y

We move all terms to the left:

7(y+2)-(2(8y-8)+7y)=0

We multiply parentheses

7y-(2(8y-8)+7y)+14=0



We calculate terms in parentheses: -(2(8y-8)+7y), so:

2(8y-8)+7y

We add all the numbers together, and all the variables

7y+2(8y-8)

We multiply parentheses

7y+16y-16

We add all the numbers together, and all the variables

23y-16

Back to the equation:

-(23y-16)



We get rid of parentheses

7y-23y+16+14=0

We add all the numbers together, and all the variables

-16y+30=0

We move all terms containing y to the left, all other terms to the right

-16y=-30

y=-30/-16

y=1+7/8

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