10a=3(a-4)+15

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Solution for 10a=3(a-4)+15 equation: 



10a=3(a-4)+15

We move all terms to the left:

10a-(3(a-4)+15)=0



We calculate terms in parentheses: -(3(a-4)+15), so:

3(a-4)+15

We multiply parentheses

3a-12+15

We add all the numbers together, and all the variables

3a+3

Back to the equation:

-(3a+3)



We get rid of parentheses

10a-3a-3=0

We add all the numbers together, and all the variables

7a-3=0

We move all terms containing a to the left, all other terms to the right

7a=3

a=3/7

a=3/7

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