3x+(2x+1)=16

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Solution for 3x+(2x+1)=16 equation: 



3x+(2x+1)=16

We move all terms to the left:

3x+(2x+1)-(16)=0

We get rid of parentheses

3x+2x+1-16=0

We add all the numbers together, and all the variables

5x-15=0

We move all terms containing x to the left, all other terms to the right

5x=15

x=15/5

x=3

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