4(x+5)=-4(x-3)+2(x+1)

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Solution for 4(x+5)=-4(x-3)+2(x+1) equation: 



4(x+5)=-4(x-3)+2(x+1)

We move all terms to the left:

4(x+5)-(-4(x-3)+2(x+1))=0

We multiply parentheses

4x-(-4(x-3)+2(x+1))+20=0



We calculate terms in parentheses: -(-4(x-3)+2(x+1)), so:

-4(x-3)+2(x+1)

We multiply parentheses

-4x+2x+12+2

We add all the numbers together, and all the variables

-2x+14

Back to the equation:

-(-2x+14)



We get rid of parentheses

4x+2x-14+20=0

We add all the numbers together, and all the variables

6x+6=0

We move all terms containing x to the left, all other terms to the right

6x=-6

x=-6/6

x=-1

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