3y+12=9y-41

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Solution for 3y+12=9y-41 equation: 



3y+12=9y-41

We move all terms to the left:

3y+12-(9y-41)=0

We get rid of parentheses

3y-9y+41+12=0

We add all the numbers together, and all the variables

-6y+53=0

We move all terms containing y to the left, all other terms to the right

-6y=-53

y=-53/-6

y=8+5/6

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