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(5x+9)/(2x-5)=0
Domain of the equation: (2x-5)!=0We multiply all the terms by the denominator
We move all terms containing x to the left, all other terms to the right
2x!=5
x!=5/2
x!=2+1/2
x∈R
(5x+9)=0
We get rid of parentheses
5x+9=0
We move all terms containing x to the left, all other terms to the right
5x=-9
x=-9/5
x=-1+4/5
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