(3y-7)(9+4y)=(6y-1)(5+2y)

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Solution for (3y-7)(9+4y)=(6y-1)(5+2y) equation: 



(3y-7)(9+4y)=(6y-1)(5+2y)

We move all terms to the left:

(3y-7)(9+4y)-((6y-1)(5+2y))=0

We add all the numbers together, and all the variables

(3y-7)(4y+9)-((6y-1)(2y+5))=0

We multiply parentheses ..

(+12y^2+27y-28y-63)-((6y-1)(2y+5))=0



We calculate terms in parentheses: -((6y-1)(2y+5)), so:

(6y-1)(2y+5)

We multiply parentheses ..

(+12y^2+30y-2y-5)

We get rid of parentheses

12y^2+30y-2y-5

We add all the numbers together, and all the variables

12y^2+28y-5

Back to the equation:

-(12y^2+28y-5)



We get rid of parentheses

12y^2-12y^2+27y-28y-28y-63+5=0

We add all the numbers together, and all the variables

-29y-58=0

We move all terms containing y to the left, all other terms to the right

-29y=58

y=58/-29

y=-2

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