7(x-4)-4(x-2)=1

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Solution for 7(x-4)-4(x-2)=1 equation: 



7(x-4)-4(x-2)=1

We move all terms to the left:

7(x-4)-4(x-2)-(1)=0

We multiply parentheses

7x-4x-28+8-1=0

We add all the numbers together, and all the variables

3x-21=0

We move all terms containing x to the left, all other terms to the right

3x=21

x=21/3

x=7

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