8x-9=(3x-1)(x+3)

Solution for 8x-9=(3x-1)(x+3) equation:

8x-9=(3x-1)(x+3)

We move all terms to the left:

8x-9-((3x-1)(x+3))=0

We multiply parentheses ..

-((+3x^2+9x-1x-3))+8x-9=0


We calculate terms in parentheses: -((+3x^2+9x-1x-3)), so:

(+3x^2+9x-1x-3)

We get rid of parentheses

3x^2+9x-1x-3

We add all the numbers together, and all the variables

3x^2+8x-3

Back to the equation:

-(3x^2+8x-3)


We add all the numbers together, and all the variables

8x-(3x^2+8x-3)-9=0

We get rid of parentheses

-3x^2+8x-8x+3-9=0

We add all the numbers together, and all the variables

-3x^2-6=0

a = -3; b = 0; c = -6;
Δ = b2-4ac
Δ = 02-4·(-3)·(-6)
Δ = -72
Delta is less than zero, so there is no solution for the equation