3y(5y-2)=-20y+8

Solution for 3y(5y-2)=-20y+8 equation:

3y(5y-2)=-20y+8

We move all terms to the left:

3y(5y-2)-(-20y+8)=0

We multiply parentheses

15y^2-6y-(-20y+8)=0

We get rid of parentheses

15y^2-6y+20y-8=0

We add all the numbers together, and all the variables

15y^2+14y-8=0

a = 15; b = 14; c = -8;
Δ = b2-4ac
Δ = 142-4·15·(-8)
Δ = 676
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{676}=26$
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(14)-26}{2*15}=\frac{-40}{30}
=-1+1/3
$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(14)+26}{2*15}=\frac{12}{30}
=2/5
$