3(y-5)=7-2(y+1)

Solution for 3(y-5)=7-2(y+1) equation:

3(y-5)=7-2(y+1)

We move all terms to the left:

3(y-5)-(7-2(y+1))=0

We multiply parentheses

3y-(7-2(y+1))-15=0


We calculate terms in parentheses: -(7-2(y+1)), so:

7-2(y+1)

determiningTheFunctionDomain
-2(y+1)+7

We multiply parentheses

-2y-2+7

We add all the numbers together, and all the variables

-2y+5

Back to the equation:

-(-2y+5)


We get rid of parentheses

3y+2y-5-15=0

We add all the numbers together, and all the variables

5y-20=0

We move all terms containing y to the left, all other terms to the right

5y=20

y=20/5

y=4