3(y-1)=2(y+10)

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Solution for 3(y-1)=2(y+10) equation: 



3(y-1)=2(y+10)

We move all terms to the left:

3(y-1)-(2(y+10))=0

We multiply parentheses

3y-(2(y+10))-3=0



We calculate terms in parentheses: -(2(y+10)), so:

2(y+10)

We multiply parentheses

2y+20

Back to the equation:

-(2y+20)



We get rid of parentheses

3y-2y-20-3=0

We add all the numbers together, and all the variables

y-23=0

We move all terms containing y to the left, all other terms to the right

y=23

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