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3x=5/2x+4
We move all terms to the left:
3x-(5/2x+4)=0
Domain of the equation: 2x+4)!=0We get rid of parentheses
x∈R
3x-5/2x-4=0
We multiply all the terms by the denominator
3x*2x-4*2x-5=0
Wy multiply elements
6x^2-8x-5=0
a = 6; b = -8; c = -5;
Δ = b2-4ac
Δ = -82-4·6·(-5)
Δ = 184
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{184}=\sqrt{4*46}=\sqrt{4}*\sqrt{46}=2\sqrt{46}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-8)-2\sqrt{46}}{2*6}=\frac{8-2\sqrt{46}}{12} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-8)+2\sqrt{46}}{2*6}=\frac{8+2\sqrt{46}}{12} $
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