x+5-3(x+1)=42-6(x-2)

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Solution for x+5-3(x+1)=42-6(x-2) equation: 



x+5-3(x+1)=42-6(x-2)

We move all terms to the left:

x+5-3(x+1)-(42-6(x-2))=0

We multiply parentheses

x-3x-(42-6(x-2))-3+5=0



We calculate terms in parentheses: -(42-6(x-2)), so:

42-6(x-2)

determiningTheFunctionDomain
-6(x-2)+42

We multiply parentheses

-6x+12+42

We add all the numbers together, and all the variables

-6x+54

Back to the equation:

-(-6x+54)



We add all the numbers together, and all the variables

-2x-(-6x+54)+2=0

We get rid of parentheses

-2x+6x-54+2=0

We add all the numbers together, and all the variables

4x-52=0

We move all terms containing x to the left, all other terms to the right

4x=52

x=52/4

x=13

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