3x2-2x=225=0

Solution for 3x2-2x=225=0 equation:

3x^2-2x=225=0

We move all terms to the left:

3x^2-2x-(225)=0

a = 3; b = -2; c = -225;
Δ = b2-4ac
Δ = -22-4·3·(-225)
Δ = 2704
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{2704}=52$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-2)-52}{2*3}=\frac{-50}{6}
=-8+1/3
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-2)+52}{2*3}=\frac{54}{6}
=9
$