X+(x+4)+x+(x+4)=72

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Solution for X+(x+4)+x+(x+4)=72 equation:



X+(X+4)+X+(X+4)=72
We move all terms to the left:
X+(X+4)+X+(X+4)-(72)=0
We add all the numbers together, and all the variables
2X+(X+4)+(X+4)-72=0
We get rid of parentheses
2X+X+X+4+4-72=0
We add all the numbers together, and all the variables
4X-64=0
We move all terms containing X to the left, all other terms to the right
4X=64
X=64/4
X=16

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