(x-2)+3x=1/2(x+6)+2

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Solution for (x-2)+3x=1/2(x+6)+2 equation: 



(x-2)+3x=1/2(x+6)+2

We move all terms to the left:

(x-2)+3x-(1/2(x+6)+2)=0



Domain of the equation: 2(x+6)+2)!=0

x∈R



We add all the numbers together, and all the variables

3x+(x-2)-(1/2(x+6)+2)=0

We get rid of parentheses

3x+x-(1/2(x+6)+2)-2=0

We multiply all the terms by the denominator


3x*2(x+6)+2)+x*2(x+6)+2)-(1-2*2(x+6)+2)=0

We add all the numbers together, and all the variables

3x*2(x+6)+2)+x*2(x+6)+2)-(1-2*2(x=0

Wy multiply elements

6x^2(x+2)+x*2(x+6)-2*2(x+2)-(1=0

We add all the numbers together, and all the variables

6x^2(x+2)+x*2(x+6)-2*2(x+2)=0

Wy multiply elements

6x^2(x+2)+2x^2(x-4x(x=0

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