3x2+7x=10

Solution for 3x2+7x=10 equation:

3x^2+7x=10

We move all terms to the left:

3x^2+7x-(10)=0

a = 3; b = 7; c = -10;
Δ = b2-4ac
Δ = 72-4·3·(-10)
Δ = 169
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{169}=13$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(7)-13}{2*3}=\frac{-20}{6}
=-3+1/3
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(7)+13}{2*3}=\frac{6}{6}
=1
$