7(w+2)=-2(6w-5)+3w

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Solution for 7(w+2)=-2(6w-5)+3w equation: 



7(w+2)=-2(6w-5)+3w

We move all terms to the left:

7(w+2)-(-2(6w-5)+3w)=0

We multiply parentheses

7w-(-2(6w-5)+3w)+14=0



We calculate terms in parentheses: -(-2(6w-5)+3w), so:

-2(6w-5)+3w

We add all the numbers together, and all the variables

3w-2(6w-5)

We multiply parentheses

3w-12w+10

We add all the numbers together, and all the variables

-9w+10

Back to the equation:

-(-9w+10)



We get rid of parentheses

7w+9w-10+14=0

We add all the numbers together, and all the variables

16w+4=0

We move all terms containing w to the left, all other terms to the right

16w=-4

w=-4/16

w=-1/4

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