4(x-3)+12=28

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Solution for 4(x-3)+12=28 equation: 



4(x-3)+12=28

We move all terms to the left:

4(x-3)+12-(28)=0

We add all the numbers together, and all the variables

4(x-3)-16=0

We multiply parentheses

4x-12-16=0

We add all the numbers together, and all the variables

4x-28=0

We move all terms containing x to the left, all other terms to the right

4x=28

x=28/4

x=7

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