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3x-5=(12+4x)/4
We move all terms to the left:
3x-5-((12+4x)/4)=0
We add all the numbers together, and all the variables
3x-((4x+12)/4)-5=0
We multiply all the terms by the denominator
3x*4)-((4x+12)-5*4)=0
We add all the numbers together, and all the variables
3x*4)-((4x+12)=0
Wy multiply elements
12x^2=0
a = 12; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·12·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation
Stosujemy wzór:$x=\frac{-b}{2a}=\frac{0}{24}=0$
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