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5(4x-2)=2(2x+11)
We move all terms to the left:
5(4x-2)-(2(2x+11))=0
We multiply parentheses
20x-(2(2x+11))-10=0
We calculate terms in parentheses: -(2(2x+11)), so:We get rid of parentheses
2(2x+11)
We multiply parentheses
4x+22
Back to the equation:
-(4x+22)
20x-4x-22-10=0
We add all the numbers together, and all the variables
16x-32=0
We move all terms containing x to the left, all other terms to the right
16x=32
x=32/16
x=2
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