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11(c-5)=10(c-5)
We move all terms to the left:
11(c-5)-(10(c-5))=0
We multiply parentheses
11c-(10(c-5))-55=0
We calculate terms in parentheses: -(10(c-5)), so:We get rid of parentheses
10(c-5)
We multiply parentheses
10c-50
Back to the equation:
-(10c-50)
11c-10c+50-55=0
We add all the numbers together, and all the variables
c-5=0
We move all terms containing c to the left, all other terms to the right
c=5
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