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3x-5(2x+4)=6-5(x-2)
We move all terms to the left:
3x-5(2x+4)-(6-5(x-2))=0
We multiply parentheses
3x-10x-(6-5(x-2))-20=0
We calculate terms in parentheses: -(6-5(x-2)), so:We add all the numbers together, and all the variables
6-5(x-2)
determiningTheFunctionDomain -5(x-2)+6
We multiply parentheses
-5x+10+6
We add all the numbers together, and all the variables
-5x+16
Back to the equation:
-(-5x+16)
-7x-(-5x+16)-20=0
We get rid of parentheses
-7x+5x-16-20=0
We add all the numbers together, and all the variables
-2x-36=0
We move all terms containing x to the left, all other terms to the right
-2x=36
x=36/-2
x=-18
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