8(x+3)-2(3+2x)=-4(2x-2)+6-4x

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Solution for 8(x+3)-2(3+2x)=-4(2x-2)+6-4x equation: 



8(x+3)-2(3+2x)=-4(2x-2)+6-4x

We move all terms to the left:

8(x+3)-2(3+2x)-(-4(2x-2)+6-4x)=0

We add all the numbers together, and all the variables

8(x+3)-2(2x+3)-(-4(2x-2)+6-4x)=0

We multiply parentheses

8x-4x-(-4(2x-2)+6-4x)+24-6=0



We calculate terms in parentheses: -(-4(2x-2)+6-4x), so:

-4(2x-2)+6-4x

determiningTheFunctionDomain
-4(2x-2)-4x+6

We add all the numbers together, and all the variables

-4x-4(2x-2)+6

We multiply parentheses

-4x-8x+8+6

We add all the numbers together, and all the variables

-12x+14

Back to the equation:

-(-12x+14)



We add all the numbers together, and all the variables

4x-(-12x+14)+18=0

We get rid of parentheses

4x+12x-14+18=0

We add all the numbers together, and all the variables

16x+4=0

We move all terms containing x to the left, all other terms to the right

16x=-4

x=-4/16

x=-1/4

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