3(3x-2)=3x+42

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Solution for 3(3x-2)=3x+42 equation: 



3(3x-2)=3x+42

We move all terms to the left:

3(3x-2)-(3x+42)=0

We multiply parentheses

9x-(3x+42)-6=0

We get rid of parentheses

9x-3x-42-6=0

We add all the numbers together, and all the variables

6x-48=0

We move all terms containing x to the left, all other terms to the right

6x=48

x=48/6

x=8

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