3x-4(4x+1)=3(x+2)+5

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Solution for 3x-4(4x+1)=3(x+2)+5 equation: 



3x-4(4x+1)=3(x+2)+5

We move all terms to the left:

3x-4(4x+1)-(3(x+2)+5)=0

We multiply parentheses

3x-16x-(3(x+2)+5)-4=0



We calculate terms in parentheses: -(3(x+2)+5), so:

3(x+2)+5

We multiply parentheses

3x+6+5

We add all the numbers together, and all the variables

3x+11

Back to the equation:

-(3x+11)



We add all the numbers together, and all the variables

-13x-(3x+11)-4=0

We get rid of parentheses

-13x-3x-11-4=0

We add all the numbers together, and all the variables

-16x-15=0

We move all terms containing x to the left, all other terms to the right

-16x=15

x=15/-16

x=-15/16

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