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(y-2)+5(y+2)=2(y-6)
We move all terms to the left:
(y-2)+5(y+2)-(2(y-6))=0
We multiply parentheses
(y-2)+5y-(2(y-6))+10=0
We get rid of parentheses
y+5y-(2(y-6))-2+10=0
We calculate terms in parentheses: -(2(y-6)), so:We add all the numbers together, and all the variables
2(y-6)
We multiply parentheses
2y-12
Back to the equation:
-(2y-12)
6y-(2y-12)+8=0
We get rid of parentheses
6y-2y+12+8=0
We add all the numbers together, and all the variables
4y+20=0
We move all terms containing y to the left, all other terms to the right
4y=-20
y=-20/4
y=-5
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