3x-4(2x+5)=3(-2)+10

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Solution for 3x-4(2x+5)=3(-2)+10 equation: 



3x-4(2x+5)=3(-2)+10

We move all terms to the left:

3x-4(2x+5)-(3(-2)+10)=0

We add all the numbers together, and all the variables

3x-4(2x+5)-4=0

We multiply parentheses

3x-8x-20-4=0

We add all the numbers together, and all the variables

-5x-24=0

We move all terms containing x to the left, all other terms to the right

-5x=24

x=24/-5

x=-4+4/5

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