7y-3=2(y-4)*

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Solution for 7y-3=2(y-4)* equation: 



7y-3=2(y-4)*

We move all terms to the left:

7y-3-(2(y-4)*)=0



We calculate terms in parentheses: -(2(y-4)*), so:

2(y-4)*

We multiply parentheses

2y-8

Back to the equation:

-(2y-8)



We get rid of parentheses

7y-2y+8-3=0

We add all the numbers together, and all the variables

5y+5=0

We move all terms containing y to the left, all other terms to the right

5y=-5

y=-5/5

y=-1

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