3x-3/3x=2

Solution for 3x-3/3x=2 equation:

3x-3/3x=2

We move all terms to the left:

3x-3/3x-(2)=0


Domain of the equation: 3x!=0

x!=0/3

x!=0

x∈R


We multiply all the terms by the denominator


3x*3x-2*3x-3=0

Wy multiply elements

9x^2-6x-3=0

a = 9; b = -6; c = -3;
Δ = b2-4ac
Δ = -62-4·9·(-3)
Δ = 144
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{144}=12$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-6)-12}{2*9}=\frac{-6}{18}
=-1/3
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-6)+12}{2*9}=\frac{18}{18}
=1
$