2x-3(x+5)=4(2x+1)-6

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Solution for 2x-3(x+5)=4(2x+1)-6 equation: 



2x-3(x+5)=4(2x+1)-6

We move all terms to the left:

2x-3(x+5)-(4(2x+1)-6)=0

We multiply parentheses

2x-3x-(4(2x+1)-6)-15=0



We calculate terms in parentheses: -(4(2x+1)-6), so:

4(2x+1)-6

We multiply parentheses

8x+4-6

We add all the numbers together, and all the variables

8x-2

Back to the equation:

-(8x-2)



We add all the numbers together, and all the variables

-1x-(8x-2)-15=0

We get rid of parentheses

-1x-8x+2-15=0

We add all the numbers together, and all the variables

-9x-13=0

We move all terms containing x to the left, all other terms to the right

-9x=13

x=13/-9

x=-1+4/9

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