(3x-4)+(5x+1)=4x-(x-7)

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Solution for (3x-4)+(5x+1)=4x-(x-7) equation: 



(3x-4)+(5x+1)=4x-(x-7)

We move all terms to the left:

(3x-4)+(5x+1)-(4x-(x-7))=0

We get rid of parentheses

3x+5x-(4x-(x-7))-4+1=0



We calculate terms in parentheses: -(4x-(x-7)), so:

4x-(x-7)

We get rid of parentheses

4x-x+7

We add all the numbers together, and all the variables

3x+7

Back to the equation:

-(3x+7)



We add all the numbers together, and all the variables

8x-(3x+7)-3=0

We get rid of parentheses

8x-3x-7-3=0

We add all the numbers together, and all the variables

5x-10=0

We move all terms containing x to the left, all other terms to the right

5x=10

x=10/5

x=2

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