3x-2(1-x)-4=5(x-2)-3(x+2)

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Solution for 3x-2(1-x)-4=5(x-2)-3(x+2) equation: 



3x-2(1-x)-4=5(x-2)-3(x+2)

We move all terms to the left:

3x-2(1-x)-4-(5(x-2)-3(x+2))=0

We add all the numbers together, and all the variables

3x-2(-1x+1)-(5(x-2)-3(x+2))-4=0

We multiply parentheses

3x+2x-(5(x-2)-3(x+2))-2-4=0



We calculate terms in parentheses: -(5(x-2)-3(x+2)), so:

5(x-2)-3(x+2)

We multiply parentheses

5x-3x-10-6

We add all the numbers together, and all the variables

2x-16

Back to the equation:

-(2x-16)



We add all the numbers together, and all the variables

5x-(2x-16)-6=0

We get rid of parentheses

5x-2x+16-6=0

We add all the numbers together, and all the variables

3x+10=0

We move all terms containing x to the left, all other terms to the right

3x=-10

x=-10/3

x=-3+1/3

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