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3(2x-1)=2x-(x+3)
We move all terms to the left:
3(2x-1)-(2x-(x+3))=0
We multiply parentheses
6x-(2x-(x+3))-3=0
We calculate terms in parentheses: -(2x-(x+3)), so:We get rid of parentheses
2x-(x+3)
We get rid of parentheses
2x-x-3
We add all the numbers together, and all the variables
x-3
Back to the equation:
-(x-3)
6x-x+3-3=0
We add all the numbers together, and all the variables
5x=0
x=0/5
x=0
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