(4x/8)(3x+6)=0

Solution for (4x/8)(3x+6)=0 equation:

(4x/8)(3x+6)=0


Domain of the equation: 8)(3x+6)!=0

x∈R


We add all the numbers together, and all the variables

(+4x/8)(3x+6)=0

We multiply parentheses ..

(+12x^2+24x)=0

We get rid of parentheses

12x^2+24x=0

a = 12; b = 24; c = 0;
Δ = b2-4ac
Δ = 242-4·12·0
Δ = 576
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{576}=24$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(24)-24}{2*12}=\frac{-48}{24}
=-2
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(24)+24}{2*12}=\frac{0}{24}
=0
$