3x-18=3x(x-18)

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Solution for 3x-18=3x(x-18) equation:



3x-18=3x(x-18)
We move all terms to the left:
3x-18-(3x(x-18))=0
We calculate terms in parentheses: -(3x(x-18)), so:
3x(x-18)
We multiply parentheses
3x^2-54x
Back to the equation:
-(3x^2-54x)
We get rid of parentheses
-3x^2+3x+54x-18=0
We add all the numbers together, and all the variables
-3x^2+57x-18=0
a = -3; b = 57; c = -18;
Δ = b2-4ac
Δ = 572-4·(-3)·(-18)
Δ = 3033
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:
$\sqrt{\Delta}=\sqrt{3033}=\sqrt{9*337}=\sqrt{9}*\sqrt{337}=3\sqrt{337}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(57)-3\sqrt{337}}{2*-3}=\frac{-57-3\sqrt{337}}{-6} $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(57)+3\sqrt{337}}{2*-3}=\frac{-57+3\sqrt{337}}{-6} $

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