If it's not what You are looking for type in the equation solver your own equation and let us solve it.
36r^2=81
We move all terms to the left:
36r^2-(81)=0
a = 36; b = 0; c = -81;
Δ = b2-4ac
Δ = 02-4·36·(-81)
Δ = 11664
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$r_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$r_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{11664}=108$$r_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-108}{2*36}=\frac{-108}{72} =-1+1/2 $$r_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+108}{2*36}=\frac{108}{72} =1+1/2 $
| -0.3x+0.8x-1=-4 | | -z^2-3z=0 | | 15−2s=3 | | 2(r−58)=48 | | 9j+26=89 | | 4s−8=8 | | 5+3r=17 | | 2b−17=1 | | 2(6x-24)=5+2x+7 | | 9+2y=19 | | 10a2-9=81 | | 5(4x+8)=-24+4 | | 16x-4=7x+5 | | 9u=7u−6 | | 6c^2-24c=0 | | m4− 2=1 | | 6+7w=5w | | 1 = m4− 2 | | 4+7x-12)=-38 | | -12=-2+2b | | 18x^2=3x | | -8b+4=-12 | | (x-2)2^-(x+3)(x+3)=2x+4 | | -31=11+3x | | 9z=8z−10 | | X-2/3=2x/5 | | 5(9-3)=w(9)-5(3) | | 1/4(5x+8)=3-3/4x | | -37=-2x+9 | | (x-2)^2-(x+3)(x+3)=2x+4 | | -6z^2+3z=0 | | 5+5b=5b+2+3 |