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10a^2-9=81
We move all terms to the left:
10a^2-9-(81)=0
We add all the numbers together, and all the variables
10a^2-90=0
a = 10; b = 0; c = -90;
Δ = b2-4ac
Δ = 02-4·10·(-90)
Δ = 3600
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{3600}=60$$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-60}{2*10}=\frac{-60}{20} =-3 $$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+60}{2*10}=\frac{60}{20} =3 $
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