3x-1/4=2(4x+1)/5

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Solution for 3x-1/4=2(4x+1)/5 equation: 



3x-1/4=2(4x+1)/5

We move all terms to the left:

3x-1/4-(2(4x+1)/5)=0

We calculate fractions


3x+(-(2(4x+1)*4)/()+()/()=0



We calculate terms in parentheses: +(-(2(4x+1)*4)/()+()/(), so:

-(2(4x+1)*4)/()+()/(

We add all the numbers together, and all the variables

-(2(4x+1)*4)/()+1

We multiply all the terms by the denominator


-(2(4x+1)*4)+1*()



We calculate terms in parentheses: -(2(4x+1)*4), so:

2(4x+1)*4

We multiply parentheses

32x+8

Back to the equation:

-(32x+8)



We add all the numbers together, and all the variables

-(32x+8)

We get rid of parentheses

-32x-8

Back to the equation:

+(-32x-8)



We get rid of parentheses

3x-32x-8=0

We add all the numbers together, and all the variables

-29x-8=0

We move all terms containing x to the left, all other terms to the right

-29x=8

x=8/-29

x=-8/29

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