(x-1)+(x+3)=(x+4)+(x-2)

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Solution for (x-1)+(x+3)=(x+4)+(x-2) equation: 



(x-1)+(x+3)=(x+4)+(x-2)

We move all terms to the left:

(x-1)+(x+3)-((x+4)+(x-2))=0

We get rid of parentheses

x+x-((x+4)+(x-2))-1+3=0



We calculate terms in parentheses: -((x+4)+(x-2)), so:

(x+4)+(x-2)

We get rid of parentheses

x+x+4-2

We add all the numbers together, and all the variables

2x+2

Back to the equation:

-(2x+2)



We add all the numbers together, and all the variables

2x-(2x+2)+2=0

We get rid of parentheses

2x-2x-2+2=0

We add all the numbers together, and all the variables

=0

x=0/1

x=0

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