(2x-1)/(3x+1)+(x+1)/x-1)=5/2

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Solution for (2x-1)/(3x+1)+(x+1)/x-1)=5/2 equation: 



(2x-1)/(3x+1)+(x+1)/x-1)=5/2

We move all terms to the left:

(2x-1)/(3x+1)+(x+1)/x-1)-(5/2)=0



Domain of the equation: (3x+1)!=0

We move all terms containing x to the left, all other terms to the right

3x!=-1

x!=-1/3

x!=-1/3

x∈R





Domain of the equation: x!=0

x∈R



We add all the numbers together, and all the variables

(2x-1)/(3x+1)+(x+1)/x-1)-(+5/2)=0

We add all the numbers together, and all the variables

(2x-1)/(3x+1)+(x+1)/x+5/2)=0

We calculate fractions


(2x-1)*x*2)/(3x+1)*x*2)+((x+1)*(3x+1)*2))/(3x+1)*x*2)+(15x^2+5x)/(3x+1)*x*2)=0

We can not solve this equation

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