6(x-3)-3(x-2)=(3-x)+5

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Solution for 6(x-3)-3(x-2)=(3-x)+5 equation: 



6(x-3)-3(x-2)=(3-x)+5

We move all terms to the left:

6(x-3)-3(x-2)-((3-x)+5)=0

We add all the numbers together, and all the variables

6(x-3)-3(x-2)-((-1x+3)+5)=0

We multiply parentheses

6x-3x-((-1x+3)+5)-18+6=0



We calculate terms in parentheses: -((-1x+3)+5), so:

(-1x+3)+5

We get rid of parentheses

-1x+3+5

We add all the numbers together, and all the variables

-1x+8

Back to the equation:

-(-1x+8)



We add all the numbers together, and all the variables

3x-(-1x+8)-12=0

We get rid of parentheses

3x+1x-8-12=0

We add all the numbers together, and all the variables

4x-20=0

We move all terms containing x to the left, all other terms to the right

4x=20

x=20/4

x=5

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