3x+6+2(x+2)=34+(x+4)

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Solution for 3x+6+2(x+2)=34+(x+4) equation: 



3x+6+2(x+2)=34+(x+4)

We move all terms to the left:

3x+6+2(x+2)-(34+(x+4))=0

We multiply parentheses

3x+2x-(34+(x+4))+4+6=0



We calculate terms in parentheses: -(34+(x+4)), so:

34+(x+4)

determiningTheFunctionDomain
(x+4)+34

We get rid of parentheses

x+4+34

We add all the numbers together, and all the variables

x+38

Back to the equation:

-(x+38)



We add all the numbers together, and all the variables

5x-(x+38)+10=0

We get rid of parentheses

5x-x-38+10=0

We add all the numbers together, and all the variables

4x-28=0

We move all terms containing x to the left, all other terms to the right

4x=28

x=28/4

x=7

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