4/5y(10y-10)=2/7(7y+14)

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Solution for 4/5y(10y-10)=2/7(7y+14) equation: 



4/5y(10y-10)=2/7(7y+14)

We move all terms to the left:

4/5y(10y-10)-(2/7(7y+14))=0



Domain of the equation: 5y(10y-10)!=0

y∈R





Domain of the equation: 7(7y+14))!=0

y∈R



We calculate fractions


(28y7/(5y(10y-10)*7(7y+14)))+(-10y1/(5y(10y-10)*7(7y+14)))=0



We calculate terms in parentheses: +(28y7/(5y(10y-10)*7(7y+14))), so:

28y7/(5y(10y-10)*7(7y+14))

We multiply all the terms by the denominator


28y7

We add all the numbers together, and all the variables

28y^7

We do not support eypression: y^7

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