20x+2(3x+10)=2x-3(3+x)

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Solution for 20x+2(3x+10)=2x-3(3+x) equation: 



20x+2(3x+10)=2x-3(3+x)

We move all terms to the left:

20x+2(3x+10)-(2x-3(3+x))=0

We add all the numbers together, and all the variables

20x+2(3x+10)-(2x-3(x+3))=0

We multiply parentheses

20x+6x-(2x-3(x+3))+20=0



We calculate terms in parentheses: -(2x-3(x+3)), so:

2x-3(x+3)

We multiply parentheses

2x-3x-9

We add all the numbers together, and all the variables

-1x-9

Back to the equation:

-(-1x-9)



We add all the numbers together, and all the variables

26x-(-1x-9)+20=0

We get rid of parentheses

26x+1x+9+20=0

We add all the numbers together, and all the variables

27x+29=0

We move all terms containing x to the left, all other terms to the right

27x=-29

x=-29/27

x=-1+2/27

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