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3x+5=20-(1/2x)

We move all terms to the left:

3x+5-(20-(1/2x))=0

Domain of the equation: 2x))!=0We add all the numbers together, and all the variables

x!=0/1

x!=0

x∈R

3x-(20-(+1/2x))+5=0

We multiply all the terms by the denominator

3x*2x))-(20-(+5*2x))+1=0

Wy multiply elements

6x^2+10x=0

a = 6; b = 10; c = 0;

Δ = b^{2}-4ac

Δ = 10^{2}-4·6·0

Δ = 100

The delta value is higher than zero, so the equation has two solutions

We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{100}=10$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(10)-10}{2*6}=\frac{-20}{12} =-1+2/3 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(10)+10}{2*6}=\frac{0}{12} =0 $

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