(27x+3+9x-5)/2=10x-2

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Solution for (27x+3+9x-5)/2=10x-2 equation: 



(27x+3+9x-5)/2=10x-2

We move all terms to the left:

(27x+3+9x-5)/2-(10x-2)=0

We add all the numbers together, and all the variables

(36x-2)/2-(10x-2)=0

We get rid of parentheses

(36x-2)/2-10x+2=0

We multiply all the terms by the denominator


(36x-2)-10x*2+2*2=0

We add all the numbers together, and all the variables

(36x-2)-10x*2+4=0

Wy multiply elements

(36x-2)-20x+4=0

We get rid of parentheses

36x-20x-2+4=0

We add all the numbers together, and all the variables

16x+2=0

We move all terms containing x to the left, all other terms to the right

16x=-2

x=-2/16

x=-1/8

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